Product of Divisors

If number is represented as p^a × q^b × r^c × ...

Where p, q, r, ... are prime factors

Number of divisors d = (a + 1)(b + 1)(c + 1) ....

and product of divisors = No^d/2

In case of 22. = 2^1 × 11^1 so number of divisors d = (1 + 1)(1 + 1) = 4

Product of divisors = 22^4/2 = 22² = 484

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The positive divisors are 1,2,11, and 22. Their product is 22^2 = 484

All positive divisors of $22$ are $1,2,11,22$ .
The product $=1\times 2\times 11\times 22=484$