Product under Summation (Part 4)

$\begin{aligned} S &=& 1 + 9\left(\dfrac{1}{4}\right)^4 + 17\left(\dfrac{1\cdot 5}{4\cdot 8}\right)^4 + 25\left(\dfrac{1\cdot 5\cdot 9}{4\cdot 8\cdot 12}\right)^4 + \ldots \\ &=& 1 + \sum_{r=1}^{\infty} \left[ (8r+1) \prod_{k=1}^{r} \left(\dfrac{4k-3}{4k}\right)^4 \right] \end{aligned}$

Given that $S$ can be represented as $\dfrac{A^{\frac{3}{2}} \pi^{-\frac{B}{C}}}{\Gamma^2\left(\dfrac{D}{E}\right)}$ where $A,B,C,D$ and $E$ are positive integers with $\gcd (B,C) = \gcd(D,E) = 1$ .

Evaluate $A+B+C+D+E$

See Also : Part 1 , Part 2 , Part 3