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Algebra Level pending

Al can do a piece of work in 14 days, and working together, Al and Bob can do the same amount of work in 10 days. In what time can Bob alone do the work ?

16 35 20 27 28

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2 solutions

Tom Engelsman
Mar 4, 2021

If x x be Bob's time alone, then we require:

1 x + 1 14 = 1 10 1 x = 14 10 140 = 1 35 x = 35 \frac{1}{x} + \frac{1}{14} = \frac{1}{10} \Rightarrow \frac{1}{x} = \frac{14-10}{140} = \frac{1}{35} \Rightarrow \boxed{x=35} days.

Bob works 10 ÷ \div 4 4 = = 2.5 2.5 times slower than Al, therefore:

14 14 × \times 2.5 2.5 = = 35 \boxed{35} \Longrightarrow Bob's work time (days)

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