Professor X \mathfrak{X} and his experiments! -1

Professor X \mathfrak{X} is a very ingenious scientist and researcher.

Once Professor X \mathfrak{X} was doing some experiments in his laboratory related to heat and thermal expansion. He took a metal ball and heated it until its temperature increased by 30 C . 30\ ^{\circ}\text{C}. Then he found that the volume of the metal ball increased by 0.18 % 0.18\% .

Assuming isotropic behavior of the metal ball, calculate the coefficient of linear expansion of the metal and help Professor X \mathfrak{X} in his research.


The answer is 0.00002.

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1 solution

Nelvson Shine
May 11, 2014

For a solid, we can ignore the effects of pressure on the material, and the volumetric thermal expansion coefficient can be written :

Δ V V Δ T \frac{\Delta V}{V * \Delta T} = α V \alpha_V

since Δ V = \Delta V = 0.18 100 \frac{0.18}{100} V or 18 10000 V \frac{18}{10000} V , Δ T = 30 \Delta T = 30 , and α V = 3 α L \alpha_V = 3 \alpha_L then

Δ V V Δ T \frac{\Delta V}{V * \Delta T} = 3 α L 3\alpha_L

Δ V V Δ T 3 \frac{\Delta V}{V * \Delta T*3} = α L \alpha_L

18 10000 V V Δ T 3 \frac{ \frac{18}{10000} V }{V * \Delta T*3} = α L \alpha_L

α L \alpha_L = 18 10000 3 30 \frac{18}{10000*3*30}

α L \alpha_L = 0.00002 0.00002

Thus the answer is 0.00002 0.00002 or 2e-5

Same method here!

Maharnab Mitra - 7 years, 1 month ago

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