Professor $\mathfrak{X}$ and his experiments!-2

Classical Mechanics Level 4

Now professor $\mathfrak{X}$ is doing some experiment related to Rotational Mechanics. For his experiment, he took a stick of length $0.7 \text{m}$ and throws it up in the air. At the moment the stick leaves his hand, the speed of the stick's end is Zero . The stick completes $10$ turns just as it is caught by the Professor at the initial release point. Professor $\mathfrak{X}$ found that height raised by Center Of Mass of the stick is H . Can you find H in metre and help Professor in his experiments? ( Assumption : Take $\pi$ = $\dfrac{22}{7}$ )

The answer is 5.5.

1 solution

Bhaskar Pandey
Feb 14, 2018

After been thrown the stick covers an angle of 2 $\pi$ $\times$ 10 in t seconds.

Thus $\omega$ $=$ 2 $\pi$ $\times$ 10 $\div$ t

v= $\omega$ $\times$ r

From newton's law of motion we have:

t $=$ 2 $\times$ v $\div$ a

s=v $\times$ v $\div$ (2 $\times$ a)

now the rest is substitution.

Professor X \mathfrak{X} X and his experiments!-2

The answer is 5.5.

1 solution

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Professor $\mathfrak{X}$ and his experiments!-2