Profit and Loss problem 1 by Dhaval Furia

Algebra Level pending

A shopkeeper sells two tables, each procured at cost price $p$ , to Amal and Asim at a profit of $20\%$ and at a loss of $20\%$ , respectively.

Amal sells his table to Bimal at a profit of $30\%$ , while Asim sells his table to Barun at a loss of $30\%$ .

If the amounts paid by Bimal and Barun are $x$ and $y$ respectively, then $\frac {x - y}{p} = ?$

0.50

1.2

1

0.7

1 solution

A Former Brilliant Member
May 14, 2020

Amal pays Rs. $\dfrac{6p}{5}$ , and Asim pays Rs. $\dfrac{4p}{5}$ to the shopkeeper. Therefore Bimal pays Amal Rs. $\dfrac{39p}{25}$ and Barun pays Asim Rs. $\dfrac{14p}{25}$ .

So, $x=\dfrac{39p}{25}, y=\dfrac{14p}{25}\implies x-y=p\implies \dfrac{x-y}{p}=\boxed 1$ .

Profit and Loss problem 1 by Dhaval Furia

1 solution

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