Profs in GSCHS
Probability
Level
1
The ages of 5 boys are 5,6,6,8,10. calculate the standard deviation of their ages.
1.99
3.21
1.79
2.65
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1 solution
Standard Deviation = √{( (1/n) sigma(x^2) ) - [mean(x)]^2 )} √(52.2-49) = 1.79