Progressions
Number Theory
Level
2
If a,b,c are in G.P. and a^1/x=b^1/y=c^1/z then x,y,z are in
G.P.
A.P.
H.P.
A.P. and G.P. but not H.P.
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1 solution
Let them all be equal to K a=K^x, b=K^y, c=k^z, since,a,b,c are in GP, b^2=ac, K^2y=K^x+z, therefore 2y=x+z, therefore they are in AP