Projectile Motion

Classical Mechanics Level 3

A ball is projected horizontally with a speed v from the top of a plane inclined at an angle 45 degrees with the horizontal. How far from the point of projection will the ball strike the plane?

v 2 g \frac { { v }^{ 2 } }{ g } 2 2 v 2 g \sqrt { 2 } \frac { { 2v }^{ 2 } }{ g } 2 v 2 g \sqrt { 2 } \frac { { v }^{ 2 } }{ g } 2 v 2 g \frac { { 2v }^{ 2 } }{ g }

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1 solution

Connor Colombe
Jul 24, 2015

This is my first submitted solution to any problem so all feedback is welcome!

5 Helpful 1 Interesting 0 Brilliant 0 Confused

Moderator note:

Simple standard approach.

What is the angle that the ball should be projected at in order to reach the furthest distance for when it first strikes the plane?

It wont let me post the image of my work but I arrived at θ=pi/8

Connor Colombe - 5 years, 10 months ago

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