Projectile motion in electric field

In the above picture, a charged particle enters a uniform electric field at the point O O in the direction perpendicular to the electric field, and moves along the blue dotted projectile path O P Q O \rightarrow P \rightarrow Q \rightarrow . Now, suppose that it takes the same amount of time for the particle to move from O O to P P and from P P to Q . Q. Also suppose that the potential difference between O O and P P is V . V. Then what is the potential difference between P P and Q ? Q? (Ignore the gravitational force.)

2 V 2 V 3 V 3 V V V 2 V \sqrt{2} V

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2 solutions

Hemant Kumar
May 10, 2014

just use equation of motion by using "t" as time for O to P and "2t" for O to Q and you will get their distance ratio as 4:1, which means that if the downward distance in given case is "x" than in the required case it would be "3x", which means V will also be "3V". As int.(E.dl)=V.

Bryan Dellariarte
May 20, 2014

self explanatory and research

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