Projectile or Circular ?

The figure shows the velocity and acceleration of a point like body at the intial moment of its motion. The acceleration vector of the body remains constant. The minimum radius of the curvature of trajectory of the body is :

Details and Assumptions

v = 8 m s 1 v_{\circ} = 8 ms^{-1}

a = 2 m s 1 a = 2ms^{-1}

θ = 15 0 \theta = 150^{\circ}


The answer is 8.

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2 solutions

Prakhar Bindal
Oct 14, 2015

As The Acceleration Vector Remains Constant So Its Magnitude Will Obviously Remain Constant.

We Know that

Radius Of Curvature = v*v/a

where "a" is the component of total acceleration perpendicular to the direction of instantaneous velocity.

For R To Be minimum the component of "a" perpendicular to velocity should be maximum.That Can Happen

When The Whole Acceleration Vector Becomes Perpendicular To Velocity. Hence We Need To Find The Time

When Velocity Vector Will Be Perpendicular To Acceleration Vector .

So Simply We Can Write The Velocity Vector At Any instant of time t using the first equation of kinematics in

vector form (v=u+at). then we can take dot product of velocity vector and acceleration vector and put it

equal to zero to get the required time . Now we can backsubstitute this time into the expression for velocity

vector to get the magnitude of velocity at that instant.

A level 1 question.

Aaron Jerry Ninan - 4 years, 10 months ago

v= v0-root 3 /2 at

A Former Brilliant Member - 4 years, 9 months ago

after resolving a in parallel and perpendicular components of v , we get acos60 = v^2/r solving it we get r=8

Mv Saketh - 3 years, 8 months ago

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acos60=1 v^2= 64 then r should be = 64

Abhishek Maurya - 2 years, 10 months ago
Jafar Badour
Apr 27, 2015

hhh 2 easy

Can you please explain what you did?

Abhijeet Verma - 5 years, 12 months ago

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He did physics

Bhagirath Sarvaiya - 2 years, 11 months ago

حلّك مصنج، حيث حلّي أفضل

ahmad arab - 6 years, 1 month ago

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Ok,...but what is it?

Abhijeet Verma - 5 years, 9 months ago

Wrong answer bro

Aditi Priyadarshni - 3 years ago

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Did you solve it that you are saying it is wrong, if did ,upload!

Bhagirath Sarvaiya - 2 years, 11 months ago

What did you just do?

Subhiksha ND - 5 years, 9 months ago

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Physics bro

Bhagirath Sarvaiya - 2 years, 11 months ago

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