Projectile + Vertical Circle = Double Trouble

A heavy particle is suspended by a string of length L L from a fixed point O O . The particle is given a horizontal velocity v v . The string slacks at some angle and particle proceeds on a projectile path. The particle proceeds such that after becoming a projectile it passes through the point of suspension.

If the value of v 2 v^2 can be expressed as v 2 = g L tan ( x ) v^2 = gL \ \tan(x) , for positive acute angle x x then find the measure of x x in degrees.

Details And Assumptions :

  • Take acceleration due to gravity to be constant 10 m/sec 2 10 \text{ m/sec}^2 .

  • The initial motion of the particle (that is before becoming a projectile) is motion along a vertical circle (motion is in vertical plane).

  • At the instant of slacking the tension in the string will become zero.

  • The string is light and inextensible.

  • Neglect air resistance and consider the particle to be a point mass.

This is not original.


The answer is 75.

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1 solution

Rahul Badenkal
Jun 9, 2015

Perfect Solution Upvoted! +1

Prakhar Bindal - 6 years ago

Source is HC Verma - Concepts of physics if anyone if interested

Pratyush Pandey - 4 years, 7 months ago

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M S - 3 years, 1 month ago

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