Projectiling?

Classical Mechanics Level 3

A particle is projected horizontally with speed u u from a point A which is 10 m 10 m above the ground. If particle hits the inclined plane perpendicularly at point B. ( g = 10 m s − 1 ) g=10 ms^{-1})

Q1. Find the horizontal speed with which the particle was projected.

Q2. Find the length OB along the inclined plane.

Q3. Find the speed at point B.

10 3 2 , 20 2 3 , 10 3 10\sqrt{\frac{3}{2}}, \frac{20\sqrt{2}}{3}, \frac{10}{\sqrt{3}} 10 2 3 , 20 2 3 , 20 3 10\sqrt{\frac{2}{3}}, \frac{20\sqrt{2}}{3}, \frac{20}{\sqrt{3}} 20 20 3 , 20 3 , 10 3 20\sqrt{\frac{20}{3}}, 20\sqrt{3}, 10\sqrt{3} 20 3 , 10 3 , 20 3 \frac{20}{3}, \frac{10}{\sqrt{3}}, \frac{20}{\sqrt{3}}

Rishabh Tripathi by Rishabh Tripathi , 22, India

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1 solution

Ahmed Hossain
Nov 23, 2016

1=(gt)/u; gt=u; again; 10-.5gt^2=ut; 10-.5gt^2=gt^2; (3/2)gt^2=10; t^2=(2*10)/(3g); t=(2/3)^.5; u=10(2/3)^.5; hence the answer is the last option

6 Helpful 0 Interesting 0 Brilliant 2 Confused

Agr aap ans.upload kr rhe Ho Toh easy language me kiijiye na.. At least samj to aaye

Devesh Saraswat - 2 years, 10 months ago

Please explain the 2nd and 3rd part of the question properly very fat. .....please

Sai Pallavi - 2 years, 10 months ago

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