Proof that 2=0 !

Algebra Level 2

2 = 1 + 1 2=1+1

(1) so 2 = 1 + 1 2=1+\sqrt{1}

(2) so 2 = 1 + ( − 1 ) ( − 1 ) 2=1+ \sqrt{(-1)(-1)}

(3) so 2 = 1 + − 1 − 1 2=1+ \sqrt{-1}\sqrt{-1}

(4) so 2 = 1 + ( i ) ( i ) 2=1+(i)(i)

(5) so 2 = 1 + i 2 2=1+i^2

(6) so 2 = 1 + − 1 2=1+-1

(7) so 2 = 0 2=0

Think it is true? If you don't think so, try to find out which line(1-7) the error that you think it is in.

6 4 2 no error 3 7 5 1

Justin Arun by Justin Arun , 15, United Kingdom

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2 solutions

X X
May 30, 2018

− 1 × − 1 = − 1 , ( − 1 ) ( − 1 ) = 1 \sqrt{-1}\times\sqrt{-1}=-1,\sqrt{(-1)(-1)}=1

1 Helpful 0 Interesting 0 Brilliant 0 Confused

You told me to prove that 2 = 0! 0! = 1

wiru :) - 10 months, 4 weeks ago
Justin Arun
May 29, 2018

The answer is '3' as you cannot find the square root of each in such way that the numbers are negative!

0 Helpful 0 Interesting 0 Brilliant 0 Confused

Even know is false,but there are square root of negative numbers,which was " i i ",It only seen on complex plain,so you don't know it true.

Phạm Hoàng - 3 years ago

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