Properties of the Determinant II

Algebra Level 3

Some matricies, like the Vandermonde matrix , have a determinant with a cute factorisation.

If 1 a 1 a 1 2 1 a 2 a 2 2 1 a 3 a 3 2 0 \begin{vmatrix} 1 & a_1 & a_1^2 \\ 1 & a_2 & a_2^2 \\ 1 & a_3 & a_3^2\end{vmatrix} \neq 0 , what can we say about a 1 a_1 , a 2 a_2 , and a 3 a_3 ?

a 1 a_1 , a 2 a_2 , and a 3 a_3 are positive a 1 a_1 , a 2 a_2 , and a 3 a_3 are equal a 1 a_1 , a 2 a_2 , and a 3 a_3 sum to zero a 1 a_1 , a 2 a_2 , and a 3 a_3 are distinct a 1 a_1 , a 2 a_2 , and a 3 a_3 are nonzero

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1 solution

Adam K
Apr 23, 2016

We know the factorization of the determinant of the Vandermonde matrix of size n × n n \times n is given by the product:

1 i < j n ( λ j λ i ) \prod_{1\leq i\lt j \leq n}(\lambda_j - \lambda_i)

Since this has n = 3 n=3 , then the determinant is ( a 2 a 1 ) ( a 3 a 1 ) ( a 3 a 2 ) (a_2-a_1)(a_3-a_1)(a_3-a_2) . (There are other ways to find this, but the factorization is hard). If this is to be nonzero, then none of a 2 a 1 a_2-a_1 , a 3 a 1 a_3-a_1 or a 3 a 2 a_3-a_2 can be zero. Therefore a 1 a_1 , a 2 a_2 and a 3 a_3 are distinct.

Nice solution! (+1) Small typo: It should be i < j i<j in the product, of course.

Otto Bretscher - 5 years, 1 month ago

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