Some matricies, like the Vandermonde matrix , have a determinant with a cute factorisation.
If ∣ ∣ ∣ ∣ ∣ ∣ 1 1 1 a 1 a 2 a 3 a 1 2 a 2 2 a 3 2 ∣ ∣ ∣ ∣ ∣ ∣ = 0 , what can we say about a 1 , a 2 , and a 3 ?
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Nice solution! (+1) Small typo: It should be i < j in the product, of course.
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We know the factorization of the determinant of the Vandermonde matrix of size n × n is given by the product:
1 ≤ i < j ≤ n ∏ ( λ j − λ i )
Since this has n = 3 , then the determinant is ( a 2 − a 1 ) ( a 3 − a 1 ) ( a 3 − a 2 ) . (There are other ways to find this, but the factorization is hard). If this is to be nonzero, then none of a 2 − a 1 , a 3 − a 1 or a 3 − a 2 can be zero. Therefore a 1 , a 2 and a 3 are distinct.