Property of Direct Sum 2

Algebra Level pending

Suppose V 1 V_1 and V 2 V_2 are vector spaces over the field F , we have following proposition:

For all vector space W W over F and linear maps g j : V j W , j = 1 , 2 , g_j:V_j\rightarrow W,j=1,2, there exists a unique linear map g ˉ : V 1 V 2 W \bar g:V_1\oplus V_2\rightarrow W such that g j = g ˉ ι j , j = 1 , 2 , g_j=\bar g\circ\iota_j,j=1,2, where ι j : V j V 1 V 2 \iota_j:V_j\rightarrow V_1\oplus V_2 denotes canonical injection.

Conversely, if vector space V V over F and linear maps i j : V j V , j = 1 , 2 i_j:V_j\rightarrow V,j=1,2 satisfy following condition:

For all vector space W W over F and linear maps g j : V j W , j = 1 , 2 , g_j:V_j\rightarrow W,j=1,2, there exists a unique linear map g ~ : V W \tilde g:V\rightarrow W such that g j = g ~ i j , j = 1 , 2 , g_j=\tilde g\circ i_j,j=1,2,

must V V be isomorphic to V 1 V 2 V_1\oplus V_2 ?

No Yes

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1 solution

Brian Moehring
Nov 12, 2018

The following diagram is commutative

so that g ~ f ~ i j = g ~ ι j = i j = id V i j f ~ g ~ ι j = f ~ i j = ι j = id V 1 V 2 ι j \tilde g \circ \tilde f \circ i_j = \tilde g \circ \iota_j = i_j = \text{id}_V \circ i_j \\ \tilde f \circ \tilde g \circ \iota_j = \tilde f \circ i_j = \iota_j = \text{id}_{V_1\oplus V_2} \circ \iota_j which, by the uniqueness of the linear maps guaranteed by the propositions, implies g ~ f ~ = id V f ~ g ~ = id V 1 V 2 V V 1 V 2 \tilde g \circ \tilde f = \text{id}_V \qquad \tilde f \circ \tilde g = \text{id}_{V_1\oplus V_2} \quad \implies \quad V \simeq V_1\oplus V_2

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