Property of Period Again!

Algebra Level 4

Given that fundamental period of g ( x ) , h ( x ) g(x),h(x) are A , B A,B respectively. Which A , B A,B are natural numbers. And f ( x ) = g ( x ) + h ( x ) f(x)=g(x)+h(x) q ( x ) = g ( x ) × h ( x ) q(x)=g(x)×h(x) 1 ) 1) Is it necessary that fundamental period of f ( x ) f(x) is l c m ( A , B ) lcm(A, B) ?

2 ) 2) Is it necessary that fundamental period of q ( x ) q(x) is l c m ( A , B ) lcm(A, B) ?

Fundamental period, T T , means the smallest number such that f ( x + T ) = f ( x ) f(x+T) =f(x) .

1) Yes, 2) No 1) No, 2) Yes 1) No, 2) No 1) Yes, 2) Yes

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3 solutions

Chan Tin Ping
Feb 26, 2018

Case 1 ) 1) : Let g ( x ) = s i n ( π x ) , h ( x ) = s i n ( π x ) + 5 g(x)=sin(\pi x),h(x)=-sin(\pi x)+5 It is obvious that fundamental period of g ( x ) = 2 , h ( x ) = 2 g(x)=2, h(x)=2 . However, f ( x ) = 5 f(x)=5 ,which is a constant function. Hence, the answer of question 1 ) 1) is N o \large No .

Case 2 ) 2) : Let g ( x ) = t a n ( π x ) , h ( x ) = 2 c o t ( π x ) g(x)=tan(\pi x), h(x)=2cot(\pi x) It is obvious that fundamental period of g ( x ) = 1 , h ( x ) = 1 g(x)=1,h(x)=1 . However, f ( x ) = 2 f(x)=2 , which is a constant function. Hence the answer is N o \large No .

* At last, I would like to apologize because the question 'Property of Period' I posted before is W r o n g \large Wrong .

Note: There are actually functions where f ( x ) f(x) has a non-zero fundamental period that is not (a multiple of) \lcm ( A , B ) \lcm (A,B) .

In the case of g ( x ) g(x) , there is a better counterexample where g ( x ) g(x) is non-periodic, and hence there is no fundamental period.

Calvin Lin Staff - 3 years, 3 months ago
Nivedit Jain
Mar 1, 2018

Consider an example of f(x)=sin²x and g(x)=cos²x

Cosider speacial case when f ( x ) f(x) and g ( x ) g(x) have same period p p .Divide the period into two halves. There might be cases in which f ( x ) f(x) in second halve behaves as g ( x ) g(x) in 1st halve and vise versa. In this case their product​ and sum have a period of p 2 \frac{p}{2} .

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