Lee and James are walking from X to Y at the same time. They walked at an opposite direction, by means Lee started from X and James started on Y. Their proportion of their speed is 6 : 5 respectively.
When they met, Lee slows down by 25% whereas James got faster by 20%. When James reached X, Lee still has a distance of 25 km left to walk to Y.
Ask what is the distance from X to Y?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Let's say the distance from X to Y is a.
The point where James and Lee meet is 5/11a from Y and 6/11a from X. We also know the ratio of their speeds is 6:5 or 6k:5k.
After they meet, 5k gets increased by 20%, so it becomes 6k whereas 6k gets decreased by 25% to get 4.5k.
The total distance travelled by Lee now is 6/11a+4.5/11a=10.5/11a The total distance travelled by James now is 5/11a+6/11a=a
As we know, he finishes the distance at a whereas Lee is 25km off at 10.5a/11, hence a-10.5a/11=25 0.5a/11=25 0.5a=275 a=550
Hence the total distance is 550km