Protruding Percentages

Algebra Level 1

Sam's height is 25% less than Jay's height. How much is Jay's height more than Sam's height?

33 1 3 \dfrac {1}{3} % 30 30 % 25 25 % 66 2 3 \dfrac{2}{3} %

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Anuj Shikarkhane by Anuj Shikarkhane , 19, India

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2 solutions

Parveen Soni
Oct 26, 2014

Consider sam height as S and Jay Height as J
as per given J=S+(25% of J )
now solving above gives
J=4S/3 i.e J=S+(S/3)
hence J is more than 1/3 of S i.e 100/3 % of Sam

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Chelsea Long
Jul 31, 2015

If Sam's height is 25% less than Jay's height, then divide Jay's height into 4 equal parts and subtract 1. Sam's height makes up the remaining 3 parts. To get Jay's height from Sam's height, we would need to add what is equivalent to one of the 3 parts, also known as 1/3 of Sam's height.

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