P(Square-free)

k k is a random positive integer in [ 1 , n ] [1,n] . Let p ( n ) p(n) the probability of k k being square-free.

What is lim n p ( n ) \displaystyle\lim_{n\to\infty} p(n) ?


Clarification: A positive integer a a is square-free if a \sqrt{a} is in the simplified radical form.

For example, 2 , 15 , 66 2,15,66 are square-free, and 4 , 45 , 98 4,45,98 are not.


The answer is 0.6079.

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1 solution

Michael Mendrin
Oct 13, 2018

The asymptotic value is 1 ζ ( 2 ) 0.6079... \dfrac{1}{\zeta(2)} \approx 0.6079...

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