Pull up the Gun

Eight clay targets are arranged as shown above. In how many different orders can these targets be shot if no target can be shot unless the one below it has been shot?


The answer is 560.

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1 solution

Eli Ross Staff
Feb 5, 2016

There are 8 ! 8! ways to shoot the targets, ignoring the rule.

There are 3 ! , 2 ! , 3 ! 3!,2!,3! ways for the relative order of shooting the targets in each column, but only 1 order is valid, per the rules.

Thus, the number of valid orders is 8 ! 3 ! × 2 ! × 3 ! = 560. \frac{8!}{3! \times 2! \times 3!} = 560.

Remark: Another way of thinking about this is to label the targets A 1 , A 2 , A 3 , B 1 , B 2 , C 1 , C 2 , C 3 A_1,A_2,A_3,B_1,B_2,C_1,C_2,C_3 and make a similar argument about the number of words you can form if the A i A_i are indistinguishable; in other words, it is the number of distinct words than can be made with 3 As, 2 Bs, and 3 Cs.

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