Pursuit and chase

Point A moves uniformly with velocity v that is continually "aimed" at point B which in turn moves rectilinearly and uniformly with velocity u < v u<v . At the initial moment of time v v is perpendicular to u u and the points are separated by a distance L L .

If at some instant their velocities make certain angle (say x x ) and by that time the distance traversed by A perpendicular to the motion of B is L 4 \dfrac L4 , find the value of the angle x x if v = 2 u v=2u .


The answer is 81.786.

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Spandan Senapati
Aug 16, 2016

There is not much physics involved here as I would say.Just you need to resolve velocities along axes, write differentials use cool substitutions for solving and you get the required answer.A powerful tool would be to write the velocity of approach.

I get Angle as 81.786 degrees We need to solve a quadratic in cosine Whose roots are -1 and 1/7 As an angle of 180 degrees is not possible(nothing >90 is possible) We find arccos(1/7) Which is the answer :)

Suhas Sheikh - 3 years ago

Log in to reply

Hey I'm not sure but my calc's didn't say so.

Spandan Senapati - 2 years, 11 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...