A passer by gives you the following puzzle:
If counted in pairs one remains
If counted in threes,two will remain
If counted in fours, three will remain
If counted in fives, four will remain
If counted in sixes, five will remain
If counted in sevens, nothing will remain
If this number is lower than 150, what is it?
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We can easily see that on adding 1 the number becomes divisible by 2,3,4,5 & 6. so the successor is divisible by 60. this means our number is either 59 or 119. (In general it is 60n-1). As we have only 2 numbers, just check the remainder with 7.