What is the value of the expression:
1 + 2 + 3 + ⋯ + 4 9 + 5 0 + 4 9 + ⋯ + 3 + 2 + 1 ?
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
take the middle no. and make it a square value which gives the answer. in this problem 50 is the middle no. and then making 50^2 gives 2500
Well,that's how I solved it.
mid term square here 50 so 2500
50^2 = 2500
take sum of 1 to 49 and 1 to 50 using famous fromula for sume of consecutive numbers then put them together.
means the pyramid has 50 lines which is also the middle number, therefore 50^2 = 2500
c
great
i solved it
50^2 gives 2500
Did the long way round
square of highest term= n n=50 50=2500
Refer to the solution of this problem which suggests that 1 + 2 + 3 + . . + ( n − 1 ) + n + ( n − 1 ) + . . . + 3 + 2 + 1 = n 2 .
Using this fact, we can solve the problem easily like this ---->
1 + 2 + 3 + . . . . + 4 9 + 5 0 + 4 9 + . . . . . + 3 + 2 + 1 = 5 0 2 = 2 5 0 0
That's very correct
another way of solving the problem is (49) (50)/2 +(50) (51)/2....this is simply N(N+1)/2
Log in to reply
Yes, that's how the formula of the sum = n 2 was derived. See the link I posted along with this solution. See the proof I wrote there. We use the formula 1 + 2 + 3 + . . . . + q = 2 q ( q + 1 ) to derive this expression -->
S = 1 + 2 + 3 + . . . . + ( n − 1 ) + n + ( n − 1 ) + . . . . + 3 + 2 + 1 = n 2 .
50^2=2500
1 + 2 + 3 + ⋯ + 4 9 + 5 0 + 4 9 + ⋯ + 3 + 2 + 1 = ( 1 + 2 + ⋯ + 4 9 ) × 2 + 5 0 = ( 5 0 × 2 4 ) + 2 5 × 2 + 5 0 = ( 1 2 0 0 + 2 5 ) × 2 + 5 0 = 1 2 2 5 × 2 + 5 0 = 2 4 5 0 + 5 0 = 2 5 0 0
It's pretty easy. All you have to do is square the middle number of the expression , which is 50 over here.
Probably it's not the best, but I solved this question this way: using the Gauss sum, the sum of 1 + 2 + 3 + ... + 50 = 1275. Then, 1 + 2 + 3 + ... + 48 = 1176. The sum 49 + 1176 = 1225. So, 1275 + 1225 = 2500.
sum of n term of series 1+2+3+------------- is n(n+1)/2 so 49 50/2 + 50 + 49 50/2
Having this succession 1+2+3+4 ....... 49+50+49 ..........+4+3+2+1 +1+2+3+4 +(n–1) + n ....... 49+50+49........ +(n–1) + n ..... +4+3+2+1 = n^2 50^2 = 2500
50(50+1)/2+49(49+1)/2=(50/2)(51+49)=50*100/2=50^2=2500
We know that from the previous problems, the pyramids follow the pattern of n^2. Hence, taking the middle no 50 as 50^2 =2500 is the answer we get.
2(1+2+3+.........................+49)+50 will be2500
(x-2)+(x-1)+x+(x-2)+(x-1)= X^2
It is just the square of 50 the highest term in the sequence.
A famous mathmatician said, to find the sum of numbers: (first number x last number) x number of numbers divided by 2. So simply use this equation to find the sum until 50 (1+50)x 50 Divided by 2 =1275 Than because you already have 50, Find the sum of numbers between 1 and 49 (1+49)x49 Dixided by 2 =1225 Than add 1275+1225 =2500
since we know that 1+2+...+(n+1)+n+(n+1)+...+2+1=n^2 by comparing given equation and above equation we find that n=50 so 50^2=2500
Total nos are from 1 to 50 in acsending ,than in decending so sum is 50X50 =2500 Ans K.K.GARG.India
sum of n no`s upto n= n (n+1)/2; so solution is 2 (49*(49+1)/2) + 50 = 2500
Mid of the number = 50 So, 50^2 = 2500
Problem Loading...
Note Loading...
Set Loading...
It's equal to 2 × ( 1 + 2 + 3 + 4 + 5 + . . . . . . + 4 0 + 4 1 + 4 2 + 4 4 + 5 0 ) − 5 0 = ( 5 1 × 5 0 ) − 5 0
= 5 0 × 5 0 = 2 5 0 0