Pythagoras Would Be Proud

Level 2

Consider the sequence 5 , 12 , 35 , 612 , 93635 , 5,12,35,612,93635,\ldots

What comes next?

4382766512 4383756612 4383766611 4383756514 4383756613

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1 solution

Michael Mendrin
May 12, 2016

Follow the pattern

5 2 + 12 2 = ( 12 + 1 ) 2 { 5 }^{ 2 }+{ 12 }^{ 2 }={ \left( 12+1 \right) }^{ 2 }
12 2 + 35 2 = ( 35 + 2 ) 2 { 12 }^{ 2 }+{ 35 }^{ 2 }={ \left( 35+2 \right) }^{ 2 }
35 2 + 612 2 = ( 612 + 1 ) 2 { 35 }^{ 2 }+{ 612 }^{ 2 }={ \left( 612+1 \right) }^{ 2 }
612 2 + 93635 2 = ( 93635 + 2 ) 2 { 612 }^{ 2 }+{ 93635 }^{ 2 }={ \left( 93635+2 \right) }^{ 2 }
93635 2 + 4383756612 2 = ( 4383756612 + 1 ) 2 { 93635 }^{ 2 }+{ 4383756612 }^{ 2 }={ \left( 4383756612+1 \right) }^{ 2 }
4383756612 2 + 4804330508313429635 2 = ( 4804330508313429635 + 2 ) 2 { 4383756612 }^{ 2 }+{ 4804330508313429635 }^{ 2 }={ \left( 4804330508313429635+2 \right) }^{ 2 }

etc.

Is it a coincidence that

i N , a i + 2 \forall i \in \mathbb{N}, a_{i+2} ends in a i a_i

(where the sequence is just a i a_i )

Wen Z - 4 years, 7 months ago

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