Pythagorean Identity

Geometry Level 2

Use the Pythagorean identity sin 2 ( x ) + cos 2 ( x ) = 1 \sin^2(x) + \cos^2(x) = 1 to find the value of cos ( x ) \cos(x) if sin 2 ( x ) + 2 cos ( x ) 2 = 0 \sin^2(x) + 2\cos(x) - 2 = 0 . Enter your answer as the value of cos ( x ) \cos(x) .


The answer is 1.

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1 solution

Marta Reece
May 12, 2017

sin 2 ( x ) + 2 cos ( x ) 2 = 0 \sin^2(x) + 2\cos(x) - 2 = 0

sin 2 ( x ) + 2 cos ( x ) sin 2 ( x ) cos 2 ( x ) 1 = 0 \sin^2(x) + 2\cos(x) - \sin^2(x)-\cos^2(x)-1 = 0

2 cos ( x ) cos 2 ( x ) 1 = 0 2\cos(x) -\cos^2(x)-1 = 0

cos 2 ( x ) 2 cos ( x ) + 1 = 0 \cos^2(x)-2\cos(x)+1 = 0

( c o s ( x ) 1 ) 2 = 0 (cos(x) -1)^2 = 0

c o s ( x ) = 1 cos(x)=\boxed{1}

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