Q9

Geometry Level 3

ABCD is a square. From the diagonal BD, a length BX is cut off equal to BA. From X, a straight line XY is drawn perpendicular to BD to meet AD at Y. Then AB+AY=?

This question is a part of my set NMTC 2015 .
2BD BD B D 3 \frac { BD }{ \sqrt { 3 } } 3 B D \sqrt { 3 } BD B D 2 \frac { BD }{ \sqrt { 2 } } 2 B D \sqrt { 2 } BD

Satyajit Ghosh by Satyajit Ghosh , 21, India

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