Quadratic and Floor (part 2)

Algebra Level 5

x 2 25 x + b = 0 \large x^2-25\lfloor x\rfloor +b=0

At most, how many distinct real roots can the above equation has, over the real number b b ?

Notation : \lfloor \cdot \rfloor denotes the floor function .

2 4 12 8 10 6 Infinitely many More than 12 but finitely many

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1 solution

Chan Lye Lee
Jun 12, 2016

Note that the graph of y = x 2 25 x + b y=x^2-25 \lfloor x \rfloor +b is formed by lots of curves (which 'closed to' segments of gradient 2 x 25 2x-25 if x x is large) and "bounded" between the graphs of y = x 2 25 x + b y=x^2-25x+b and y = x 2 25 ( x 1 ) + b y=x^2-25(x-1)+b .

The largest number of intersection points between y = x 2 25 x + b y=x^2-25 \lfloor x \rfloor +b and y = 0 y=0 is 10 \boxed{10} , from the graph shown, when is closed to vertex of the parabolas.

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