Quadratic Equation [1]

Algebra Level 3

If a a and b b are roots of quadratic equation 2 x 2 + 3 x 3 = 0 2x^2+3x-3=0 , what is the value of 4 a 3 b + 6 a 2 b 4a^3b+6a^2b ?

-11 -12 -9 9 12

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1 solution

Chew-Seong Cheong
Oct 13, 2019

If a a and b b are roots of 2 x 2 + 3 x 3 = 0 2x^2 + 3x - 3 = 0 , by Vieta's formula we have a b = 3 2 ab = - \frac 32 , and 2 a 2 + 3 a 3 = 0 2a^2 + 3a - 3 = 0 or 2 a 2 + 3 a = 3 2a^2 + 3a = 3 . Then 4 a 2 b + 6 a 2 b = 2 a b ( 2 a 2 + 3 a ) = 2 ( 3 2 ) ( 3 ) = 9 4a^2b+6a^2b = 2ab (2a^2+3a) = 2 \left(-\frac 32\right) (3) = \boxed{-9} .

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