Quadratic without Linear

Algebra Level 5

Let α \alpha and β \beta be the two roots of the quadratic equation 3 x 2 + 48 x 7 = 0. 3x^2+48x-7=0. If the quadratic equation with the roots α + k \alpha+k and β + k \beta+k has no linear term, what is the value of k ? k?

8 8 9 9 7 7 6 6

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3 solutions

Mikhaella Layos
Apr 24, 2014

Since the quadratic equation with no linear term (the coefficient of x is 0) has roots ( α + k ) (α+k) and ( β + k ) (β+k) , then by Vieta’s formulas, we have: ( α + k ) + ( β + k ) = 0 (α+k)+(β+k)=0 α + β + 2 k = 0 α+β+2k=0
Since α and β are the roots of 3 x 2 + 48 x 7 = 0 3x^{2}+48x-7=0 , this implies that α + β = 16 α+β=-16 . Substituting this in α + β + 2 k = 0 α+β+2k=0 , we get 16 + 2 k = 0 2 k = 16 k = 8 -16+2k=0 ⇒ 2k=16 ⇒ \boxed{k=8}

How can you get the a+b=-16

Lahsg Hdbdjdjj - 4 years, 7 months ago

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Yeah thats what stumped me

Blood Blood - 4 years, 7 months ago

Vietas formula is x2+ax+b=x2-(p+q)x+pq

In this case a=48/3=16=-(p+q)

Sam Kozman - 4 years, 7 months ago

I'm not sure, but is calling roots alpha and beta standard protocol for nomenclature? I thought they were usually used for angles?

Ethan Ko - 4 years, 6 months ago

Use the quadratic formula to find a and B (the roots); [-48 + and - sqrt(48^2 - 4 3 -7)] / 2*3.

You get 0.14452 and -16.14452.

a + B = -16

Junno Martinez - 4 years, 6 months ago
Lim Reon
Mar 16, 2014

a+b=-16 so a+b+2k=0 then K=8

Ashutosh Sharma
Feb 11, 2018

is it level 5 really?

I know right! And it is 355 points!!!

Yashas Ravi - 1 year, 11 months ago

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