An algebra problem by vishwathiga jayasankar
Algebra
Level
3
Find the number of negative roots to the equation .
1
4
3
2
0
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1 solution
Based on Descartes' Rule of Signs, to find the number of possible negative real roots (I'm assuming we are looking for real roots here), you find the number of sign changes in f(-x). f ( − x ) = x 4 + 5 x − 1 4 . There is one sign change, so at most there can be one negative root.