Quadratics Expansions

Algebra Level 3

x 4 2 x 2 3 x 2 + 6 x 2 2 x 3 x + 6 = 0 \frac{x^4 - 2x^2 - 3x^2 +6}{x^2 - \sqrt{2}x - \sqrt{3}x +\sqrt{6}} = 0

Solve this expression for roots of variable x . x.

\sqrt{3} , \sqrt{2}
  • \sqrt{3} , \sqrt{2}
\sqrt{3} , - \sqrt{2} -\sqrt{3} , - \sqrt{2}

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

William Isoroku
Dec 30, 2014

Leave it to the graphing calculator.

Arshad R Shaikh
Jul 29, 2014

by calculating

                   x=\sqrt{3}, -\sqrt{3}, \sqrt{2}, -\sqrt{2}
but this expansion is not define for \sqrt{3} and \sqrt{2}

so right answer is -\sqrt{3}, -\sqrt{2}

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...