In the above diagram, find the quantity of the electric charge
in the capacitor when the switch has been closed for a long time.
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Assume potential at C be 0V. Now potential at B and D will be 11V and 17V respectively.
Apply Kirchoff's current law at point A to find voltage. (You may also use Kirchoff's voltage law!)
Let potential at A be V 4 V − 1 7 + 2 V − 1 1 + 3 V = 0 ⟹ V = 9 V
Now potential difference between plates of capacitor=11-9=2V
q = C V ⟹ q = 1 0 × 2 = 2 0 microcoulombs