Quantity of electric charge

In the above diagram, find the quantity of the electric charge Q Q in the capacitor when the switch has been closed for a long time.

20 μ C 20 \mu C 30 μ C 30 \mu C 3 μ C 3 \mu C 2 μ C 2 \mu C

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1 solution

Pranjal Jain
Oct 8, 2014

Diagram Diagram

Assume potential at C be 0V. Now potential at B and D will be 11V and 17V respectively.

Apply Kirchoff's current law at point A to find voltage. (You may also use Kirchoff's voltage law!)

Let potential at A be V V 17 4 + V 11 2 + V 3 = 0 V = 9 V \frac{V-17}{4}+\frac{V-11}{2}+\frac{V}{3}=0 \implies V=9V

Now potential difference between plates of capacitor=11-9=2V

q = C V q = 10 × 2 = 20 q=CV \implies q=10 \times 2=20 microcoulombs

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