A particle in a one-dimensional quantum well is governed by a variant of the time-independent Schrodinger equation, expressed in terms of a non-normalized wave function Ψ N ( x ) .
The quantities V and E are the potential energy and total energy, respectively.
− d x 2 d 2 Ψ N ( x ) + V ( x ) Ψ N ( x ) = E Ψ N ( x )
Let us consider a case in which E = 2 . 5 . The potential varies as follows:
V ( x ) = ∞ x < 0 V ( x ) = x 0 ≤ x ≤ x f V ( x ) = ∞ x > x f x f ≈ 3 . 0 2 6 7 (a zero crossing of Ψ N ( x ) )
The values of Ψ N ( x ) and its first spatial derivative at x = 0 are (see graphic):
Ψ N ( 0 ) = 0 ( d x d Ψ N ) ( 0 ) = 1
Note that the potential energy V ( x ) exceeds E for x > 2 . 5 , and yet the particle still has a finite non-zero probability of being measured anywhere inside the well.
The probability of detecting the particle within the region a ≤ x ≤ b is:
P ( a ≤ x ≤ b ) = ∫ 0 x f ∣ Ψ N ( x ) ∣ 2 d x ∫ a b ∣ Ψ N ( x ) ∣ 2 d x
What is the probability of detecting the particle in the region ( 0 ≤ x ≤ 1 ) ? If the probability is P , give your answer as ⌊ 1 0 0 P ⌋ .
Note: This problem lends itself well to numerical solution
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