Queen's Domain

Logic Level 2

A queen stands on an otherwise empty standard ( 8 × 8 8\times8 ) chessboard.

What is the maximum number of squares that are accessible to the queen in a single valid move?

Assumption :

Standing still does not count as a move.


The answer is 27.

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1 solution

Shourya Pandey
Apr 28, 2016

Relevant wiki: Chess Puzzles

The number of "rook-like " moves that the queen can make , starting from any square, is always 14 14 , so it suffices to maximise the number of "bishop-like" moves. Note that the "rook-like" and "bishop-like" moves are mutually exclusive and exhaustive.

Note that a diagonal in a chessboard can have at most 8 8 squares, and at most 7 7 other squares that a queen can access if she is already on that diagonal. So there can be at most 7 + 7 = 14 7+7 = 14 "bishop-like" moves she can make. But equality can't hold, because the two longest diagonals are oppositely coloured. So no more than 13 13 such moves can be made. Equality can clearly hold when the queen stands on some central square.

The answer is 14 + 13 = 27 14+13=27 .

If u dont mind could u plz explain it using figures/diagrams to make it more clear or can anyone else plz.? By the way nice explanation+1.

Rishabh Tiwari - 5 years, 1 month ago

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