Ques. -25

Calculus Level 3

lim n ( n ! n n ) 1 n = ? \displaystyle \lim_{n \to \infty} \left( \frac{n!}{n^n} \right)^{\frac{1}{n}}=?


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e 4 π \frac{4}{\pi} doesn't exist. 1 e \frac{1}{e}

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3 solutions

Deepanshu Gupta
Feb 25, 2015

L = lim n ( r = 1 n r n ) 1 n ln L = lim n 1 n r = 1 n ln r n 0 1 ln x d x = 1 L = e 1 \displaystyle{L=\lim _{ n\rightarrow \infty }{ { (\prod _{ r=1 }^{ n }{ \cfrac { r }{ n } } ) }^{ \cfrac { 1 }{ n } } } \\ \ln { L } =\lim _{ n\rightarrow \infty }{ { \cfrac { 1 }{ n } \sum _{ r=1 }^{ n }{ \ln { \cfrac { r }{ n } } } } } \equiv \int _{ 0 }^{ 1 }{ \ln { x } dx } =-1\\ \boxed { L={ e }^{ -1 } } }

Ingenius Method !! +1

A Former Brilliant Member - 6 years, 3 months ago

Wow ..... great approach .... thank you for the solution :)

Abhinav Raichur - 5 years, 11 months ago
Pi Han Goh
Feb 25, 2015

An alternative solution is to consider the sequence, a n = n ! n n a_n = \frac {n!}{n^n} , we need to prove that it converge by root test.

can you explain it?

Abhimanyu Singh - 5 years, 11 months ago
Kartik Sharma
Feb 25, 2015

Use Stirling's approximation!

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