If and , then in :
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f ′ ( x ) = 3 x 2 + 2 b x + c D = 4 b 2 − 1 2 c b 2 < c → 4 b 2 < 1 2 c → D < 0 ∀ x ∈ R f ′ ( x ) > 0 ∀ x ∈ R .
Hence, f ( x ) is strictly increasing.