Ques. -6

Algebra Level 3

e a e 2 a ( e 3 a 1 ) e b e 2 b ( e 3 b 1 ) e c e 2 c ( e 3 c 1 ) \left | \begin{array}{ccc} e^a & e^{2a} & (e^{3a}-1) \\ e^b & e^{2b} & (e^{3b}-1) \\ e^c & e^{2c} & (e^{3c}-1) \\ \end{array} \right |

if a , b a,b and c c are cube roots of unity, find the determinant of the matrix above.


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e 2 e^2 0 e 3 e^3 e

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1 solution

First put a = 1 , b = ω , c = ω 2 a=1, b=\omega ,c={ \omega }^{ 2 } . Let value of this determinant to be A A .

Then put a = ω 2 , b = ω , c = 1 a={ \omega }^{ 2 },b=\omega,c=1 . Let value of this determinant to be B B .

A = B = A A = 0 A=B=-A\Rightarrow A=0

Classic JEE style.

Just the thing I did ;)

Saswata Dasgupta - 6 years, 2 months ago

Yeahbsolutely ;)

Siddharth Bhatnagar - 6 years, 2 months ago

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