Let's draw a circle

Logic Level 3

Let a relation P = { ( x , y ) ∣ x 2 + y 2 = 1 , x , y ∈ R } P=\{ (x,y) | x^2+y^2=1, \ x,y \in \mathbb{R} \} , then P P is:

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equivalence relation symmetric relation reflexive relation symmetric, transitive relation

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Sandeep Bhardwaj by Sandeep Bhardwaj , 28, India

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2 solutions

a relation is said to be symmetric if (a,b) and (b,a) satisfy it.

the given relation is clearly symmetric.

a relation is said to be transitive if ( a,b) (b,c) (c,a) satisfy it.

the given relation is not transitive

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I didn't understand why no transitive.

Avadhoot Sinkar - 5 years, 3 months ago
Mudit Jha
Feb 23, 2016

The circle given has its centre at origin and hence is symmetric in all quadrants. If (a,b),is a point on the circle, then so is (b,a).

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