Question -5

Algebra Level 1

What is the logically equivalent proposition of p ⇔ q ? \displaystyle{p \Leftrightarrow q}?

( p ∧ q ) ∨ ( p ∧ q ) (p \wedge q) \vee (p \wedge q) ( p ⟹ q ) ∧ ( q ⟹ p ) (p \implies q) \wedge (q \implies p) ( p ⟹ q ) ∨ ( q ⟹ p ) (p \implies q) \vee (q \implies p) ( p ∨ q ) ⟹ ( p ∨ q ) (p \vee q) \implies (p \vee q)

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Sandeep Bhardwaj by Sandeep Bhardwaj , 28, India

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1 solution

Caleb Townsend
Feb 28, 2015

By the definition of p ⇔ q , p \Leftrightarrow q, p p implies q q and q q implies p . p. This is written as ( p ⇒ q ) ∧ ( q ⇒ p ) (p \Rightarrow q) \wedge (q \Rightarrow p)

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I edited that !

Deepanshu Gupta - 6 years, 3 months ago

@Sandeep Bhardwaj Overrated! No?

Pranjal Jain - 6 years, 3 months ago

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Over overrated !

Venkata Karthik Bandaru - 6 years, 3 months ago

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