Question for Abhiram Rao - 2

Chemistry Level 3

If the ionization energy of a hydrogen atom is 13.6 e V 13.6 eV , then what is the ionization energy of a carbon atom(in eV)?


The answer is 489.6.

Ashish Menon by Ashish Menon , 20, India

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1 solution

Ashish Menon
May 1, 2016

Ionization energy of given atom = Ionization energy of Hydrogen atom × Square of atomic number of given atom.

= 13.6 × 6 2 = 13.6 × 36 = 489.6 e V 13.6 × 6^2 = 13.6 × 36 = \boxed{489.6eV}

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