Question for Abhiram Rao

Chemistry Level 2

Find the molarity of aqueous solution of pure hydrochloric acid which is 15 15 % volume-by-volume.

Details and Assumptions:

  • Density of solution = 2 gm/ml . \text{Density of solution} = 2\text{ gm/ml}.
  • Density of solute = 1.5 gm/ml . \text{Density of solute} = 1.5\text{ gm/ml}.


The answer is 6.16.

Ashish Menon by Ashish Menon , 20, India

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2 solutions

Ashish Menon
Apr 26, 2016

15 % 15\% volume - by - volume implies that 15ml of HCl is present in 100ml of solution.
Now, mass of HCl = density × volume = 15 × 1.5 = 22.5g.
Similarly, mass of solution = 100 × 2 = 200g.
So, 22.5g of HCl is present in 200g of solution. Now, 200 - 22.5 = 177.5 > 22.5 which proves that HCl is solute.
Molarity = 22.5 36.5 × 1000100 = 6.16 \dfrac{22.5}{36.5} × {1000}{100} = \boxed{6.16}


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in which class you are studying

Arun Garg - 5 years, 1 month ago

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Me class 10, going to 11 after results, why?

Ashish Menon - 5 years, 1 month ago
Abhiram Rao
Oct 5, 2016

Finally learnt Solutions and got it! 😊

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