Question for Ashish Siva - 2

How many 3 - digit positive integers can be formed by using 1, 2, 3, 4, 5 without the repetition of digits?


The answer is 60.

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1 solution

Ashish Menon
May 13, 2016

The hudredths digit can be filled in 5 ways, the tens digit can be filled in 4 ways because one number is already used up and the units digit in 3 ways because two numbers are already used up, so the answer is 5 × 4 × 3 = 60 5×4×3 = \boxed{60} .

Thanks Abhiram for your question.

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