Question for Swapnil-2

Relevant wiki: Series and parallel resistors

The equivalent resistance for parellel circulits is given by the formula :- ${(\dfrac{1}{R_1} + \dfrac{1}{R_2})}^{-1}$ .
So, in this case, the equivalent resistance is ${(\dfrac{1}{100} + \dfrac{1}{100} \cdots (\text{1000 times}))}^{-1}$
= ${(\dfrac{1000}{100})}^{-1}$
= $\boxed{0.1}$ .

The equivalent resistance or total resistance of the circuit can be found using the formula:

$\Large{{ R }_{ T }=\frac { 1 }{ \frac { 1 }{ { R }_{ 1 } } +\frac { 1 }{ { R }_{ 2 } } +\frac { 1 }{ { R }_{ 3 } } +...+\frac { 1 }{ { R }_{ n } } } }$

Since there are 1000 Resistors each with $100\Omega$ :

$\Large{{ R }_{ T }=\frac { 1 }{ \frac { 1 }{ 100 } +\frac { 1 }{ 100 } +... (1000\text{ times}) } \\ \\ \\ }$

$\Large{{ R }_{ T }=\frac { 1 }{ \frac { 1000 }{ 100 } } }$

$\Large{{ R }_{ T }=\frac { 1 }{ 10 } =\boxed { 0.1\Omega } \\ }$

can u explain the title ? y it's for swapnil ?