Let be a group and let and be two subgroups of .
If both and have elements, which of the following numbers cannot be the the number of elements in the set ?
Notation:
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A group of order twelve has 4 possible subgroups. 6, 4, 3, 2. If H and K were to share the same subgroup then it would over lap. Therefore H K can only have 6 × 1 2 , 4 × 1 2 , 3 × 1 2 , 2 × 1 2 elements. Thus 6 0 is the odd one out.