Question3

Algebra Level 2

( 2 x + 3 ) 2 3 ( 2 x + 3 ) 4 = 0 (2x+3)^{2}-3(2x+3)-4=0

Solve this equation.

x = 2 , 1 2 x=2 , -\frac{1}{2} x = 1 , 7 2 x=-1 , \frac{7}{2} x = 2 , 1 2 x=-2 , \frac{1}{2} x = 1 , 7 2 x=1 , -\frac{7}{2}

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Luye Xue
Feb 13, 2015

( 2 x + 3 ) 2 3 ( 2 x + 3 ) 4 = 0 (2x+3)^{2}-3(2x+3)-4=0

( 2 x + 3 4 ) ( 2 x + 3 + 1 ) = 0 (2x+3-4)(2x+3+1)=0

( 2 x 1 ) ( 2 x + 4 ) = 0 (2x-1)(2x+4)=0

x = 2 , 1 2 x=-2,\frac{1}{2}

Well done Luyi! It is very wise that you did not expand the expression in the first place, which really takes insight. Good job!

Stanley Guo - 6 years, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...