Quite messy but easy

Algebra Level pending

1 + 2 + . . . + 2014 ( 3 5 101 ) + ( 5 100 ) + 1 + 2 + . . . + 2014 14105 1 7 + 1 \frac { 1\quad +\quad 2\quad +\quad ...\quad +\quad 2014 }{ (3\quad *\quad 5\quad *\quad 101)\quad +\quad (5\quad *\quad 100) } +\frac { 1\quad +\quad 2\quad +\quad ...\quad +\quad 2014 }{ 14105\quad *\quad \frac { 1 }{ 7 } } +\quad 1 What is the value of the equation above?


The answer is 2015.

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