Quite obvious

Algebra Level 3

Let $a,b,\alpha \in \mathbb{R}^{+}$ , such that $b>a$ . Then the expression $a-\alpha b$ is always

Non-negative Negative None of these Positive

2 solutions

Siddharth Singh
Jul 25, 2015

The answer is always $\mathbb{R}$ .

Aditya Kumar
Jul 24, 2015

The situation provided is ambiguous. It only depends on $\alpha$ . If $\alpha$ > a/b the value will be positive. If $\alpha$ <a/b it is negative. If alpha=a/b value is 000

Instead of a/b it should be 1.Because it all depend on whether alpha >1 or smaller than 1.

Naman Kapoor - 5 years, 10 months ago

It's the same

Aditya Kumar - 5 years, 10 months ago

Quite obvious

2 solutions

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