Race Between Passenger And Goods Train

Suppose the distance between the cities is x Km. then x/20 = x/60 + 50/60 ( to convert minutes into Hours ) Upon simplifying the above equation we get 2x/60 = 50/60.. Hence 2x = 50. And Hence x = 25.

(60 x)/20 - (60 x)/60 = 50 .... from here we get x = 25

Let the distance be D (in km) Time taken by the passenger train T1=Distance/Speed=D/60 hours Time taken by goods train T2=D/20 hours The time difference(T1-T2) is 50 minutes= 50/60 hours or, D/20-D/60=50/60 or, 3D/60-D/60 = 50/60 or, 3D - D = 50 or, 2D = 50 or, D = 25

L/20 - L/60 = 50/60 L=25 km

suppose distance=x, and passenger train reached in t hr. so ,goods train will reach in t+5/6 hr. thus,60t=(t+5/6) 20, solving this equation,t=5/12 so distance x= 60 5/12=25

Equation: 60(50-x)=20(50+x) ---> 3000-60x=1000+20x ---> 3000-1000-60x-20x=0 ---> 2000-80x=0 ---> 2000=80x ---> 2000/80=80x/80 ---> 25=x.

2 equation 2 unknowns T in hours D in kilometers Velocity= Distance/Time 60=D/T 20=D/(T+(50/60)) Using Calculator D=25 km

Let $x$ be the goods train's time in hours, therefore, $x-\frac {5}{6}$ is the time of the passenger train to reach the destination. Goods train's speed is 20km/h while passenger train is 60km/h. The distance of both trains are equal, therefore:

$20x=60(x-\frac {5}{6})$

$20x=60x-50$

$40x=50$

$x=1.25$

To get the distance between the 2 stations, we need to multiply speed and time.

$1.25 \times 20=25km$

Let the distance between the cities is x Km. then x/20 = x/60 + 50/60 we get 2x/60 = 50/60 Hence 2x = 50. And Hence x = 25

Write a solution. Let, the distance between the cities are=x. So, here, x/20= x/60+5/6. Answer= 25

75 min at 20 km/h - 25 min at 60km/h = 25 km