Racing and Refueling

both car will need 4 times refuelling ,not 5 times . As firstly both car are full intake … and it need to go 100mile , not 105mile … so it can complete race by taking 4 times refuel . for 1st car 100 mile -> 1945.945 s refuel time ->120s total time ->2065.945s for 2nd car 100 mile -> 1800s refuel time -> 360s total time -> 2160s As … 2065.945s < 2160s so .. i 1st car will be reach first

total 4 refuel time $$ 1st car takes $\frac{1\times 100}{185}\times 60+\frac{30\times 4}{60}=34.43 min$ $$ $$ 2ndcar takes $\frac{1\times 100}{200}\times 60+\frac{90\times 4}{60}=36 min$ $$ so choose 1st car

Ist car for refueling takes 30 secs,for 100 miles ,will require 5 times refueling that is 150 secs.+32.5 mts while 2nd car will tale 450 secs for refueling + 30 mts to cover 100 miles. So,ist racing car will take less time. ANS

K.K.GARg,India

Race length =100 miles. Fuel tank capacity=21 miles. Refueling 100/21 =4.76 times . 4.76 30 =142.8 sec for 1st car. 4.76 90 = 428.9 sec for 2 nd car. speed.. (100/185) 3600= 1945 sec first car. (100/200) 3600=1800 sec 2nd car. Time required for 1st car =1945 sec+142.8 sec. Time required for 2nd car=1800 sec+428.9 sec. Answer is first car as 2087.8 sec < 2228 sec .

car 1 will take 34.93 min (time for refuelling and time to cover 105 miles with its top speed of 185 miles/hr) whereas car 2 will take 37.5 min (time for refuelling and to cover 105 miles with its top speed of 200 miles/hr)

Great. I admire the calculations of Clemente Nemo San. Surely, the 1st Car will win the race.

both cars need to refuel 4 times => the first car will spend 304/60=2 min and the second will spend 904/60=6 min. For 100 miles, the first car need 100/18560=32.43 min, the second need 100/20060=30 min. So total time of the first is 32.43+2=34.43 min, and total time of the secon is 30+6= 36. The conclution is the first will run faster for 100 miles race

100 MILES CAN BE DIVIDED AS (21 4)+16 MILES, TIME TAKEN BY FIRST CAR = ((((21 4)+16/185) 3600)-(30 4)) SECONDS SIMILARLY U CAN FIND TIME TAKEN BY SECOND CAR

1st car.now,1st car goes first 21 miles in 408 seconds.then 1st car takes 30 seconds for refueling.on the other hand 2nd car goes first 21 miles in 378 seconds,then takes 90 seconds for refueling.for this reason,for the first 21 miles the 1st car gets 30 seconds more.for the rest of the race 1st car will get 30 seconds in every refueling time.as a result 1st car finish the race at 2063.351351 seconds.whether the 2nd car will finish the race at 2160 seconds. So we should choose the 1st car.

Total Distance(100)/Vehicle's travel cap(21) = 4.76 , 4 times refueling required for the 100 mile race.

1st vehicle calculations 185mi/hr or 3.08mi/sec when converted to seconds using Time = Distance/Speed formula to get the amount of time for 21 miles: 21mi/(3.08mi/sec) = 6.818sec, multiplied by 4.76 which is the number of 21mi in 100mi = 32.454 seconds & 120 seconds for refueling time. 1st car takes 152.454 seconds to refuel and finish the 100 miles race.

2nd vehicle calculations 200mi/hr or 3.33mi/sec when converted to seconds using Time = Distance/Speed formula to get the amount of time for 21 miles: 21mi/(3.33mi/sec) = 6.306sec, multiplied by 4.76 which is the number of 21mi in 100mi = 30.018 seconds & 360 seconds for refueling time. 2nd car takes 390.018 seconds to refuel and finish the 100 miles race.

1st car finishes the race first!

1 st car will be faster as total time taken by the first car will be{100(19.459)+4(30)=2065.9 sec} & total time taken by 2 nd car will be{100(18)+90(4)=2160 sec}

While refuelling 1st car for 90 seconds same as 2nd car it gets185 * 30 *3/3600 =4.625miles back while the 2nd car gets 200 * 90/3600=5 miles back. So first car takes less time

1st car because if the first car 30 seconds you can refuel the car and it goes for 185 miles but as of the 2nd car it takes 90 much longer than the 1st car, and of the given it goes for 200 miles so even if you just analize the given and what it ask for that should be the answer, but thats only mine,....

If there is no refueling, Car 1 needs 0.540 hours to cover a 100 mi distance while Car 2 needs 0.5 hours. But both cars need refueling 4 times so Car 1 needs 0.033 hour more while Car 2 needs 0.1 hr more to cover the distance. Therefore, Car 1 will race ahead because it will take lesser time.

CAR A; 185mile/60mins x 100mile/race = 32 mins 26 sec + (4refuel x 0,5 min) = 34 mins 26 sec CAR B; 200mile/60mins x 100mile/race = 30 mins + (4refuel x 1.5 min) = 36 mins

Car A would take 34 mins 26 sec to reach 100 miles in speed of 185mph w/ refueling time of 30 seconds. While;

Car B would take 36 Minutes to reach 100 miles in speed of 200mph w/ refueling time of 90 seconds.

so Car A will reach the Finish line 1 minute and 34 seconds a head by Car B..

find time at car A and car B. At car A 100/21 = 4.7619 whole number only. 4 times need to refuel the car. given the time required to refuel. so t1 = 4x30sec = 120 sec calculate t2 with the given velocity and distance. so (100M/185mph)x(60sec/1hr)= 32.4324sec. total time at Car A is T = t1 + t2= 120sec + 32,4324sec = 152.4324sec.

At car B 100/21 = 4.7619. 4 times need to refuel the car. t1 = 4x90sec = 360sec. t2 = (100M/200mph)x(60sec/1hr) = 30 sec. T = t1 + t2 = 360sec + 30sec = 390sec.

CAR A is fastest.

4times refueling.

1st 2 min / 2nd 6min.

1st car : 185mile/h = 21mile in 6min48s = 100mile in 32min24s.

1st Car 100 mile in 32min24s+2min = 43min24s.

2nd Car 200mile/h = 21mile in 6min18s = 100mile in 30min.

2nd Car 100mile in 30min + 6 min = 36min .

Anzar Aznzar Morocco

Both car will have to refuel 4 times and as it takes only 30 sec for the first car to refuel so only (4x30=) 120 sec + 32.4 minute =34.4 minute will be the lap time for the first car, where as the second car will take (4x90=) 360 sec + 30 minute= 36 minute to complete the lap. As 34.4<36 , the first car will win assuming 100% efficiency in all variables that effect lap time.

the first car Ist car for refueling takes 30 secs,for 100 miles ,will require 5 times refueling that is 150 secs.+32.5 mts while 2nd car will tale 450 secs for refueling + 30 mts to cover 100 miles. So,ist racing car will take less time

both of car will refueling 100/21 = 4,76 = 4 times

first car: (100/185 * 3600) + (4 30) = 2065 sec second car : (100/200 *3600) + *(4 90) = 2160 sec

1st car in 100 miles with 4 stoppages. total time taken to fueling=4 30=120sec=2 min. total time taken=2 + 60 100/185=34.43 min (approx), where as 2nd car also take 4 stoppages in 100 miles.Time taken to refueling is= 4 90=360 sec=6 min. Total time taken to cover 100 miles in =6 + 60 100/200=36 min. so, 1st car cover the 100 miles in less time .

First car will reach the destination in 34.43 minutes while the second car will reach 36 minutes. Answer is: First Car.